Aeroflot flight SU3608

Schedule for June 25

Tampa - New York City (TPA-JFK)

Domestic flight SU3608 by Aeroflot serves route within United States (TPA to JFK). The flight departs Tampa on June 25 07:15 (7:15 am) and arrives New York City, John F. Kennedy terminal «4» on June 25 09:59 (9:59 am). Flight duration is 2h 44m. This flight is operated by Delta, flight number DL2464.
SU 3608
Aeroflot
The flight is operated by Delta, flight DL2464
Departure
Arrival
07:15 / 7:15 am
09:59 / 9:59 am
June 25, Monday
June 25, Monday
 
Terminal 4
Tampa (TPA)
John F. Kennedy (JFK)
United States
New York City, United States
Flight duration: 2h 44m
Airbus A319

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