Brussels Airlines flight SN9080

Schedule for August 16

London - Houston (LHR-IAH)

International flight SN9080 by Brussels Airlines serves route from United Kingdom to United States (LHR to IAH). The flight departs London, Heathrow terminal «2» on August 16 13:40 (1:40 pm) and arrives Houston, George Bush terminal «E» on August 16 17:50 (5:50 pm). Flight duration is 10h 10m. This flight is operated by United Airlines, flight number UA4.
SN 9080
Brussels Airlines
The flight is operated by United Airlines, flight UA4
13:40 / 1:40 pm
17:50 / 5:50 pm
August 16, Thursday
August 16, Thursday
Terminal 2
Terminal E
Heathrow (LHR)
George Bush (IAH)
London, United Kingdom
Houston, United States
Flight duration: 10h 10m
Boeing 777

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