Brussels Airlines flight SN9080

Schedule for August 16

London - Houston (LHR-IAH)

International flight SN9080 by Brussels Airlines serves route from United Kingdom to United States (LHR to IAH). The flight departs London, Heathrow terminal «2» on August 16 13:40 (1:40 pm) and arrives Houston, George Bush terminal «E» on August 16 17:50 (5:50 pm). Flight duration is 10h 10m. This flight is operated by United Airlines, flight number UA4.
SN 9080
Brussels Airlines
The flight is operated by United Airlines, flight UA4
Departure
Arrival
13:40 / 1:40 pm
17:50 / 5:50 pm
August 16, Thursday
August 16, Thursday
Terminal 2
Terminal E
Heathrow (LHR)
George Bush (IAH)
London, United Kingdom
Houston, United States
Flight duration: 10h 10m
Boeing 777

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