Brussels Airlines flight SN9080 schedule

Flight schedule & details, February 21

1. Flight SN9080: London - Houston, LHR - IAH, 10h 40m

International flight SN9080 by Brussels Airlines serves route from United Kingdom to United States (LHR to IAH). The flight departs London, Heathrow terminal «2» on February 21 13:35 (1:35 pm) and arrives Houston, George Bush terminal «E» on February 21 18:15 (6:15 pm). Flight duration is 10h 40m. This flight is operated by United Airlines, flight number UA4.
SN 9080
Brussels Airlines
The flight is operated by United Airlines, flight UA4
Departure
Arrival
13:35 / 1:35 pm
18:15 / 6:15 pm
February 21, Wednesday
February 21, Wednesday
Terminal 2
Terminal E
Heathrow (LHR)
George Bush (IAH)
London, United Kingdom
Houston, United States
Flight duration: 10h 40m
Boeing 777

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