Brussels Airlines flight SN9080 schedule

Flight schedule & details, February 21

1. Flight SN9080: London - Houston, LHR - IAH, 10h 40m

International flight SN9080 by Brussels Airlines serves route from United Kingdom to United States (LHR to IAH). The flight departs London, Heathrow terminal «2» on February 21 13:35 (1:35 pm) and arrives Houston, George Bush terminal «E» on February 21 18:15 (6:15 pm). Flight duration is 10h 40m. This flight is operated by United Airlines, flight number UA4.
SN 9080
Brussels Airlines
The flight is operated by United Airlines, flight UA4
13:35 / 1:35 pm
18:15 / 6:15 pm
February 21, Wednesday
February 21, Wednesday
Terminal 2
Terminal E
Heathrow (LHR)
George Bush (IAH)
London, United Kingdom
Houston, United States
Flight duration: 10h 40m
Boeing 777

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