Brussels Airlines flight SN9080 schedule

Flight departure days

Flight schedule & details, November 23

1. Flight SN9080: London - Houston, LHR - IAH, 10h 50m

International flight SN9080 by Brussels Airlines serves route from United Kingdom to United States (LHR to IAH). The flight departs London, Heathrow terminal «2» on November 23 13:35 (1:35 pm) and arrives Houston, George Bush terminal «E» on November 23 18:25 (6:25 pm). Flight duration is 10h 50m. This flight is operated by United Airlines, flight number UA4.
SN 9080
Brussels Airlines
The flight is operated by United Airlines, flight UA4
Departure
Arrival
13:35 / 1:35 pm
18:25 / 6:25 pm
November 23, Thursday
November 23, Thursday
Terminal 2
Terminal E
Heathrow (LHR)
George Bush (IAH)
London, United Kingdom
Houston, United States
Flight duration: 10h 50m
Boeing 777

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