United Airlines flight UA4742 schedule

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1. Flight UA4742: Windsor Locks - Cleveland, BDL - CLE, 1h 54m

Windsor Locks
Cleveland
Bradley (BDL)
United Airlines
Cleveland-Hopkins (CLE)
05:50
UA4742
07:44
31 Mar
1h 54m
31 Mar
United Airlines domestic flight UA4742 departs from airport Windsor Locks, Bradley (BDL), United States on Monday, 31 March at 05:50 / 5:50 am. The flight arrives to airport Cleveland, Cleveland-Hopkins (CLE), United States on Monday, 31 March at 07:44 / 7:44 am. Flight duration is 1h 54m.
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